MathTech
Solving Differential Equations
If a Differential Equation can be written in the form
\(\frac{dy}{dx}=f(x)\)
Solve by direct integration
E.G. \(\frac{dy}{dx}=x^2\)
\(\int\frac{dy}{dx}dx=\int x^2\,dx\)
\(y=\frac{x^3}{3}+C\)
If a Differential Equation can be written in the form
\(\frac{dy}{dx}=g(x)h(y)\)
Solve by separation of variables:
divide by \(h(y)\) Integrate \(dx\)
perform two integrations if possible. Obtain implicit form with 1 constant
rearrange for y
E.G. \(\frac{dy}{dx}=x(1+y^2)\) where \(g(x)=x\) and \(h(y)=1+y^2\)
- divide by \((1+y^2)\)
\(\frac{1}{1+y^2}\frac{dy}{dx}=x\)
- Integrate dx
\(\int\frac{1}{1+y^2}\frac{dy}{dx}dx=\int x\,dx\)
- perform integrations
\(\arctan y=\frac{x^2}{2}+C\)
- rearange for y
\(y=\tan(\frac{x^2}{2}+C)\)
If a Differential Equation can be written in the form
\(\frac{dy}{dx}+g(x)y=h(x)\)
Solve by integrating factor:
\(p(x)=\exp(\int g(x)\,dx)\)
determine integrating factor \(p(x)\)
rewrite as \(\frac{d}{dx}(p(x)y)=p(x)h(x)\)
integrate dx to get \(p(x)y=\int p(x)h(x)\,dx+C\)
divide by \(p(x)\)
E.G. \(\frac{dy}{dx}=x-\frac{2xy}{x^2+1}\)
Write as
\(\frac{dy}{dx}+\frac{2xy}{x^2+1}=x (1)\)
\(g(x)=\frac{2x}{x^2+1}\, ,h(x)=x\)
- determine integrating factor
\(p(x)=exp(\int\frac{2x}{x^2+1}\,dx)\)